Metamath Proof Explorer


Theorem s7cld

Description: A length 7 string is a word. (Contributed by Mario Carneiro, 27-Feb-2016)

Ref Expression
Hypotheses s2cld.1 ⊢ φ → A ∈ X
s2cld.2 ⊢ φ → B ∈ X
s3cld.3 ⊢ φ → C ∈ X
s4cld.4 ⊢ φ → D ∈ X
s5cld.5 ⊢ φ → E ∈ X
s6cld.6 ⊢ φ → F ∈ X
s7cld.7 ⊢ φ → G ∈ X
Assertion s7cld ⊢ φ → ⟨“ ABCDEFG ”⟩ ∈ Word X

Proof

Step Hyp Ref Expression
1 s2cld.1 ⊢ φ → A ∈ X
2 s2cld.2 ⊢ φ → B ∈ X
3 s3cld.3 ⊢ φ → C ∈ X
4 s4cld.4 ⊢ φ → D ∈ X
5 s5cld.5 ⊢ φ → E ∈ X
6 s6cld.6 ⊢ φ → F ∈ X
7 s7cld.7 ⊢ φ → G ∈ X
8 df-s7 ⊢ ⟨“ ABCDEFG ”⟩ = ⟨“ ABCDEF ”⟩ ++ ⟨“ G ”⟩
9 1 2 3 4 5 6 s6cld ⊢ φ → ⟨“ ABCDEF ”⟩ ∈ Word X
10 8 9 7 cats1cld ⊢ φ → ⟨“ ABCDEFG ”⟩ ∈ Word X