Metamath Proof Explorer


Theorem s6cld

Description: A length 6 string is a word. (Contributed by Mario Carneiro, 27-Feb-2016)

Ref Expression
Hypotheses s2cld.1 ⊢ φ → A ∈ X
s2cld.2 ⊢ φ → B ∈ X
s3cld.3 ⊢ φ → C ∈ X
s4cld.4 ⊢ φ → D ∈ X
s5cld.5 ⊢ φ → E ∈ X
s6cld.6 ⊢ φ → F ∈ X
Assertion s6cld ⊢ φ → ⟨“ ABCDEF ”⟩ ∈ Word X

Proof

Step Hyp Ref Expression
1 s2cld.1 ⊢ φ → A ∈ X
2 s2cld.2 ⊢ φ → B ∈ X
3 s3cld.3 ⊢ φ → C ∈ X
4 s4cld.4 ⊢ φ → D ∈ X
5 s5cld.5 ⊢ φ → E ∈ X
6 s6cld.6 ⊢ φ → F ∈ X
7 df-s6 ⊢ ⟨“ ABCDEF ”⟩ = ⟨“ ABCDE ”⟩ ++ ⟨“ F ”⟩
8 1 2 3 4 5 s5cld ⊢ φ → ⟨“ ABCDE ”⟩ ∈ Word X
9 7 8 6 cats1cld ⊢ φ → ⟨“ ABCDEF ”⟩ ∈ Word X