Metamath Proof Explorer


Theorem sbor2

Description: One direction of sbor , using fewer axioms. Compare 19.33 . (Contributed by Steven Nguyen, 18-Aug-2023)

Ref Expression
Assertion sbor2 ⊢ t x φ ∨ t x ψ → t x φ ∨ ψ

Proof

Step Hyp Ref Expression
1 orc ⊢ φ → φ ∨ ψ
2 1 sbimi ⊢ t x φ → t x φ ∨ ψ
3 olc ⊢ ψ → φ ∨ ψ
4 3 sbimi ⊢ t x ψ → t x φ ∨ ψ
5 2 4 jaoi ⊢ t x φ ∨ t x ψ → t x φ ∨ ψ