Metamath Proof Explorer


Theorem sepab

Description: Separation Scheme (Aussonderung) in terms of a class abstraction. Prefer using the more natural statement rabexg . (Contributed by NM, 8-Jun-1994) Put in closed form. (Revised by BJ, 18-Jul-2026)

Ref Expression
Assertion sepab ⊢ A ∈ V → x | x ∈ A ∧ φ ∈ V

Proof

Step Hyp Ref Expression
1 id ⊢ A ∈ V → A ∈ V
2 ssab2 ⊢ x | x ∈ A ∧ φ ⊆ A
3 2 a1i ⊢ A ∈ V → x | x ∈ A ∧ φ ⊆ A
4 1 3 ssexd ⊢ A ∈ V → x | x ∈ A ∧ φ ∈ V