Metamath Proof Explorer


Theorem simplbda

Description: Deduction eliminating a conjunct. (Contributed by NM, 22-Oct-2007)

Ref Expression
Hypothesis simplbda.1 ⊢ φ → ψ ↔ χ ∧ θ
Assertion simplbda ⊢ φ ∧ ψ → θ

Proof

Step Hyp Ref Expression
1 simplbda.1 ⊢ φ → ψ ↔ χ ∧ θ
2 1 biimpa ⊢ φ ∧ ψ → χ ∧ θ
3 2 simprd ⊢ φ ∧ ψ → θ