Metamath Proof Explorer


Theorem spcdv

Description: Rule of specialization, using implicit substitution. Analogous to rspcdv . (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypotheses spcimdv.1 ⊢ φ → A ∈ B
spcdv.2 ⊢ φ ∧ x = A → ψ ↔ χ
Assertion spcdv ⊢ φ → ∀ x ψ → χ

Proof

Step Hyp Ref Expression
1 spcimdv.1 ⊢ φ → A ∈ B
2 spcdv.2 ⊢ φ ∧ x = A → ψ ↔ χ
3 2 biimpd ⊢ φ ∧ x = A → ψ → χ
4 1 3 spcimdv ⊢ φ → ∀ x ψ → χ