Metamath Proof Explorer


Theorem spcdv

Description: Rule of specialization, using implicit substitution. Analogous to rspcdv . (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypotheses spcimdv.1 φAB
spcdv.2 φx=Aψχ
Assertion spcdv φxψχ

Proof

Step Hyp Ref Expression
1 spcimdv.1 φAB
2 spcdv.2 φx=Aψχ
3 2 biimpd φx=Aψχ
4 1 3 spcimdv φxψχ