Metamath Proof Explorer


Theorem speimfw

Description: Specialization, with additional weakening (compared to 19.2 ) to allow bundling of x and y . Uses only Tarski's FOL axiom schemes. (Contributed by NM, 23-Apr-2017) (Proof shortened by Wolf Lammen, 5-Dec-2017)

Ref Expression
Hypothesis speimfw.2 ⊢ x = y → φ → ψ
Assertion speimfw ⊢ ¬ ∀ x ¬ x = y → ∀ x φ → ∃ x ψ

Proof

Step Hyp Ref Expression
1 speimfw.2 ⊢ x = y → φ → ψ
2 df-ex ⊢ ∃ x x = y ↔ ¬ ∀ x ¬ x = y
3 2 biimpri ⊢ ¬ ∀ x ¬ x = y → ∃ x x = y
4 1 com12 ⊢ φ → x = y → ψ
5 4 aleximi ⊢ ∀ x φ → ∃ x x = y → ∃ x ψ
6 3 5 syl5com ⊢ ¬ ∀ x ¬ x = y → ∀ x φ → ∃ x ψ