Metamath Proof Explorer


Theorem sqrtsqd

Description: Square root of square. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses resqrcld.1 φ A
resqrcld.2 φ 0 A
Assertion sqrtsqd φ A 2 = A

Proof

Step Hyp Ref Expression
1 resqrcld.1 φ A
2 resqrcld.2 φ 0 A
3 sqrtsq A 0 A A 2 = A
4 1 2 3 syl2anc φ A 2 = A