Metamath Proof Explorer


Theorem ssdif2d

Description: If A is contained in B and C is contained in D , then ( A \ D ) is contained in ( B \ C ) . Deduction form. (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypotheses ssdifd.1 ⊢ φ → A ⊆ B
ssdif2d.2 ⊢ φ → C ⊆ D
Assertion ssdif2d ⊢ φ → A ∖ D ⊆ B ∖ C

Proof

Step Hyp Ref Expression
1 ssdifd.1 ⊢ φ → A ⊆ B
2 ssdif2d.2 ⊢ φ → C ⊆ D
3 2 sscond ⊢ φ → A ∖ D ⊆ A ∖ C
4 1 ssdifd ⊢ φ → A ∖ C ⊆ B ∖ C
5 3 4 sstrd ⊢ φ → A ∖ D ⊆ B ∖ C