Metamath Proof Explorer


Theorem ssdifss

Description: Preservation of a subclass relationship by class difference. (Contributed by NM, 15-Feb-2007)

Ref Expression
Assertion ssdifss ⊢ A ⊆ B → A ∖ C ⊆ B

Proof

Step Hyp Ref Expression
1 difss ⊢ A ∖ C ⊆ A
2 sstr ⊢ A ∖ C ⊆ A ∧ A ⊆ B → A ∖ C ⊆ B
3 1 2 mpan ⊢ A ⊆ B → A ∖ C ⊆ B