Metamath Proof Explorer


Theorem ssdifss

Description: Preservation of a subclass relationship by class difference. (Contributed by NM, 15-Feb-2007)

Ref Expression
Assertion ssdifss ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∖ 𝐶 ) ⊆ 𝐵 )

Proof

Step Hyp Ref Expression
1 difss ⊢ ( 𝐴 ∖ 𝐶 ) ⊆ 𝐴
2 sstr ⊢ ( ( ( 𝐴 ∖ 𝐶 ) ⊆ 𝐴 ∧ 𝐴 ⊆ 𝐵 ) → ( 𝐴 ∖ 𝐶 ) ⊆ 𝐵 )
3 1 2 mpan ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐴 ∖ 𝐶 ) ⊆ 𝐵 )