Metamath Proof Explorer


Theorem sstr

Description: Transitivity of subclass relationship. Theorem 6 of Suppes p. 23. (Contributed by NM, 5-Sep-2003)

Ref Expression
Assertion sstr ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐴 ⊆ 𝐶 )

Proof

Step Hyp Ref Expression
1 sstr2 ⊢ ( 𝐴 ⊆ 𝐵 → ( 𝐵 ⊆ 𝐶 → 𝐴 ⊆ 𝐶 ) )
2 1 imp ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐴 ⊆ 𝐶 )