Metamath Proof Explorer


Theorem sseq2i

Description: An equality inference for the subclass relationship. (Contributed by NM, 30-Aug-1993)

Ref Expression
Hypothesis sseq1i.1 ⊢ A = B
Assertion sseq2i ⊢ C ⊆ A ↔ C ⊆ B

Proof

Step Hyp Ref Expression
1 sseq1i.1 ⊢ A = B
2 sseq2 ⊢ A = B → C ⊆ A ↔ C ⊆ B
3 1 2 ax-mp ⊢ C ⊆ A ↔ C ⊆ B