Metamath Proof Explorer


Theorem ssfz12

Description: Subset relationship for finite sets of sequential integers. (Contributed by Alexander van der Vekens, 16-Mar-2018)

Ref Expression
Assertion ssfz12 ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K … L ⊆ M … N → M ≤ K ∧ L ≤ N

Proof

Step Hyp Ref Expression
1 eluz ⊢ K ∈ ℤ ∧ L ∈ ℤ → L ∈ ℤ ≥ K ↔ K ≤ L
2 1 biimp3ar ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → L ∈ ℤ ≥ K
3 eluzfz1 ⊢ L ∈ ℤ ≥ K → K ∈ K … L
4 2 3 syl ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K ∈ K … L
5 eluzfz2 ⊢ L ∈ ℤ ≥ K → L ∈ K … L
6 2 5 syl ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → L ∈ K … L
7 ssel2 ⊢ K … L ⊆ M … N ∧ K ∈ K … L → K ∈ M … N
8 ssel2 ⊢ K … L ⊆ M … N ∧ L ∈ K … L → L ∈ M … N
9 elfzuz3 ⊢ L ∈ M … N → N ∈ ℤ ≥ L
10 eluz2 ⊢ K ∈ ℤ ≥ M ↔ M ∈ ℤ ∧ K ∈ ℤ ∧ M ≤ K
11 eluz2 ⊢ N ∈ ℤ ≥ L ↔ L ∈ ℤ ∧ N ∈ ℤ ∧ L ≤ N
12 pm3.21 ⊢ L ≤ N → M ≤ K → M ≤ K ∧ L ≤ N
13 12 3ad2ant3 ⊢ L ∈ ℤ ∧ N ∈ ℤ ∧ L ≤ N → M ≤ K → M ≤ K ∧ L ≤ N
14 11 13 sylbi ⊢ N ∈ ℤ ≥ L → M ≤ K → M ≤ K ∧ L ≤ N
15 14 a1i ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → N ∈ ℤ ≥ L → M ≤ K → M ≤ K ∧ L ≤ N
16 15 com13 ⊢ M ≤ K → N ∈ ℤ ≥ L → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → M ≤ K ∧ L ≤ N
17 16 3ad2ant3 ⊢ M ∈ ℤ ∧ K ∈ ℤ ∧ M ≤ K → N ∈ ℤ ≥ L → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → M ≤ K ∧ L ≤ N
18 10 17 sylbi ⊢ K ∈ ℤ ≥ M → N ∈ ℤ ≥ L → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → M ≤ K ∧ L ≤ N
19 elfzuz ⊢ K ∈ M … N → K ∈ ℤ ≥ M
20 18 19 syl11 ⊢ N ∈ ℤ ≥ L → K ∈ M … N → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → M ≤ K ∧ L ≤ N
21 8 9 20 3syl ⊢ K … L ⊆ M … N ∧ L ∈ K … L → K ∈ M … N → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → M ≤ K ∧ L ≤ N
22 21 ex ⊢ K … L ⊆ M … N → L ∈ K … L → K ∈ M … N → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → M ≤ K ∧ L ≤ N
23 22 com4t ⊢ K ∈ M … N → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K … L ⊆ M … N → L ∈ K … L → M ≤ K ∧ L ≤ N
24 7 23 syl ⊢ K … L ⊆ M … N ∧ K ∈ K … L → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K … L ⊆ M … N → L ∈ K … L → M ≤ K ∧ L ≤ N
25 24 ex ⊢ K … L ⊆ M … N → K ∈ K … L → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K … L ⊆ M … N → L ∈ K … L → M ≤ K ∧ L ≤ N
26 25 com24 ⊢ K … L ⊆ M … N → K … L ⊆ M … N → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K ∈ K … L → L ∈ K … L → M ≤ K ∧ L ≤ N
27 26 pm2.43i ⊢ K … L ⊆ M … N → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K ∈ K … L → L ∈ K … L → M ≤ K ∧ L ≤ N
28 27 com14 ⊢ L ∈ K … L → K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K ∈ K … L → K … L ⊆ M … N → M ≤ K ∧ L ≤ N
29 6 28 mpcom ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K ∈ K … L → K … L ⊆ M … N → M ≤ K ∧ L ≤ N
30 4 29 mpd ⊢ K ∈ ℤ ∧ L ∈ ℤ ∧ K ≤ L → K … L ⊆ M … N → M ≤ K ∧ L ≤ N