Metamath Proof Explorer


Theorem sslin

Description: Add left intersection to subclass relation. (Contributed by NM, 19-Oct-1999)

Ref Expression
Assertion sslin A B C A C B

Proof

Step Hyp Ref Expression
1 ssrin A B A C B C
2 incom C A = A C
3 incom C B = B C
4 1 2 3 3sstr4g A B C A C B