Metamath Proof Explorer


Theorem sslin

Description: Add left intersection to subclass relation. (Contributed by NM, 19-Oct-1999)

Ref Expression
Assertion sslin ⊢ A ⊆ B → C ∩ A ⊆ C ∩ B

Proof

Step Hyp Ref Expression
1 ssrin ⊢ A ⊆ B → A ∩ C ⊆ B ∩ C
2 incom ⊢ C ∩ A = A ∩ C
3 incom ⊢ C ∩ B = B ∩ C
4 1 2 3 3sstr4g ⊢ A ⊆ B → C ∩ A ⊆ C ∩ B