Metamath Proof Explorer


Theorem ssn0rex

Description: There is an element in a class with a nonempty subclass which is an element of the subclass. (Contributed by AV, 17-Dec-2020)

Ref Expression
Assertion ssn0rex ⊢ A ⊆ B ∧ A ≠ ∅ → ∃ x ∈ B x ∈ A

Proof

Step Hyp Ref Expression
1 ssrexv ⊢ A ⊆ B → ∃ x ∈ A x ∈ A → ∃ x ∈ B x ∈ A
2 n0rex ⊢ A ≠ ∅ → ∃ x ∈ A x ∈ A
3 1 2 impel ⊢ A ⊆ B ∧ A ≠ ∅ → ∃ x ∈ B x ∈ A