Metamath Proof Explorer


Theorem ssn0rex

Description: There is an element in a class with a nonempty subclass which is an element of the subclass. (Contributed by AV, 17-Dec-2020)

Ref Expression
Assertion ssn0rex ( ( 𝐴 ⊆ 𝐵 ∧ 𝐴 ≠ ∅ ) → ∃ 𝑥 ∈ 𝐵 𝑥 ∈ 𝐴 )

Proof

Step Hyp Ref Expression
1 ssrexv ⊢ ( 𝐴 ⊆ 𝐵 → ( ∃ 𝑥 ∈ 𝐴 𝑥 ∈ 𝐴 → ∃ 𝑥 ∈ 𝐵 𝑥 ∈ 𝐴 ) )
2 n0rex ⊢ ( 𝐴 ≠ ∅ → ∃ 𝑥 ∈ 𝐴 𝑥 ∈ 𝐴 )
3 1 2 impel ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐴 ≠ ∅ ) → ∃ 𝑥 ∈ 𝐵 𝑥 ∈ 𝐴 )