Metamath Proof Explorer


Theorem stji1i

Description: Join of components of Sasaki arrow ->1. (Contributed by NM, 24-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses stle.1 ⊢ A ∈ C ℋ
stle.2 ⊢ B ∈ C ℋ
Assertion stji1i ⊢ S ∈ States → S ⁡ ⊥ ⁡ A ∨ ℋ A ∩ B = S ⁡ ⊥ ⁡ A + S ⁡ A ∩ B

Proof

Step Hyp Ref Expression
1 stle.1 ⊢ A ∈ C ℋ
2 stle.2 ⊢ B ∈ C ℋ
3 1 choccli ⊢ ⊥ ⁡ A ∈ C ℋ
4 1 2 chincli ⊢ A ∩ B ∈ C ℋ
5 3 4 pm3.2i ⊢ ⊥ ⁡ A ∈ C ℋ ∧ A ∩ B ∈ C ℋ
6 inss1 ⊢ A ∩ B ⊆ A
7 4 1 chsscon3i ⊢ A ∩ B ⊆ A ↔ ⊥ ⁡ A ⊆ ⊥ ⁡ A ∩ B
8 6 7 mpbi ⊢ ⊥ ⁡ A ⊆ ⊥ ⁡ A ∩ B
9 stj ⊢ S ∈ States → ⊥ ⁡ A ∈ C ℋ ∧ A ∩ B ∈ C ℋ ∧ ⊥ ⁡ A ⊆ ⊥ ⁡ A ∩ B → S ⁡ ⊥ ⁡ A ∨ ℋ A ∩ B = S ⁡ ⊥ ⁡ A + S ⁡ A ∩ B
10 5 8 9 mp2ani ⊢ S ∈ States → S ⁡ ⊥ ⁡ A ∨ ℋ A ∩ B = S ⁡ ⊥ ⁡ A + S ⁡ A ∩ B