Metamath Proof Explorer


Theorem submcld

Description: Submonoids are closed under the monoid operation. (Contributed by Thierry Arnoux, 4-May-2025)

Ref Expression
Hypotheses submcld.1 ⊢ + ˙ = + M
submcld.2 ⊢ φ → S ∈ SubMnd ⁡ M
submcld.3 ⊢ φ → X ∈ S
submcld.4 ⊢ φ → Y ∈ S
Assertion submcld ⊢ φ → X + ˙ Y ∈ S

Proof

Step Hyp Ref Expression
1 submcld.1 ⊢ + ˙ = + M
2 submcld.2 ⊢ φ → S ∈ SubMnd ⁡ M
3 submcld.3 ⊢ φ → X ∈ S
4 submcld.4 ⊢ φ → Y ∈ S
5 1 submcl ⊢ S ∈ SubMnd ⁡ M ∧ X ∈ S ∧ Y ∈ S → X + ˙ Y ∈ S
6 2 3 4 5 syl3anc ⊢ φ → X + ˙ Y ∈ S