Metamath Proof Explorer


Theorem sum9cubes

Description: The sum of the first nine perfect cubes is 2025. (Contributed by SN, 30-Mar-2025)

Ref Expression
Assertion sum9cubes ⊢ ∑ k = 1 9 k 3 = 2025

Proof

Step Hyp Ref Expression
1 9nn0 ⊢ 9 ∈ ℕ 0
2 sumcubes ⊢ 9 ∈ ℕ 0 → ∑ k = 1 9 k 3 = ∑ k = 1 9 k 2
3 1 2 ax-mp ⊢ ∑ k = 1 9 k 3 = ∑ k = 1 9 k 2
4 arisum ⊢ 9 ∈ ℕ 0 → ∑ k = 1 9 k = 9 2 + 9 2
5 1 4 ax-mp ⊢ ∑ k = 1 9 k = 9 2 + 9 2
6 8nn0 ⊢ 8 ∈ ℕ 0
7 1nn0 ⊢ 1 ∈ ℕ 0
8 sq9 ⊢ 9 2 = 81
9 8p1e9 ⊢ 8 + 1 = 9
10 9cn ⊢ 9 ∈ ℂ
11 ax-1cn ⊢ 1 ∈ ℂ
12 9p1e10 ⊢ 9 + 1 = 10
13 10 11 12 addcomli ⊢ 1 + 9 = 10
14 6 7 1 8 9 13 decaddci2 ⊢ 9 2 + 9 = 90
15 2nn0 ⊢ 2 ∈ ℕ 0
16 4nn0 ⊢ 4 ∈ ℕ 0
17 5nn0 ⊢ 5 ∈ ℕ 0
18 eqid ⊢ 45 = 45
19 0nn0 ⊢ 0 ∈ ℕ 0
20 4t2e8 ⊢ 4 ⋅ 2 = 8
21 20 oveq1i ⊢ 4 ⋅ 2 + 1 = 8 + 1
22 21 9 eqtri ⊢ 4 ⋅ 2 + 1 = 9
23 5t2e10 ⊢ 5 ⋅ 2 = 10
24 15 16 17 18 19 7 22 23 decmul1c ⊢ 45 ⋅ 2 = 90
25 14 24 eqtr4i ⊢ 9 2 + 9 = 45 ⋅ 2
26 25 oveq1i ⊢ 9 2 + 9 2 = 45 ⋅ 2 2
27 16 17 deccl ⊢ 45 ∈ ℕ 0
28 27 nn0cni ⊢ 45 ∈ ℂ
29 2cn ⊢ 2 ∈ ℂ
30 2ne0 ⊢ 2 ≠ 0
31 28 29 30 divcan4i ⊢ 45 ⋅ 2 2 = 45
32 5 26 31 3eqtri ⊢ ∑ k = 1 9 k = 45
33 32 oveq1i ⊢ ∑ k = 1 9 k 2 = 45 2
34 sq45 ⊢ 45 2 = 2025
35 3 33 34 3eqtri ⊢ ∑ k = 1 9 k 3 = 2025