Metamath Proof Explorer


Theorem syl5eqr

Description: An equality transitivity deduction. (Contributed by NM, 5-Aug-1993)

Ref Expression
Hypotheses syl5eqr.1 B = A
syl5eqr.2 φ B = C
Assertion syl5eqr φ A = C

Proof

Step Hyp Ref Expression
1 syl5eqr.1 B = A
2 syl5eqr.2 φ B = C
3 1 eqcomi A = B
4 3 2 syl5eq φ A = C