Metamath Proof Explorer


Theorem tgcgrneq

Description: Congruence and equality. (Contributed by Thierry Arnoux, 27-Aug-2019)

Ref Expression
Hypotheses tkgeom.p P=BaseG
tkgeom.d -˙=distG
tkgeom.i I=ItvG
tkgeom.g φG𝒢Tarski
tgcgrcomlr.a φAP
tgcgrcomlr.b φBP
tgcgrcomlr.c φCP
tgcgrcomlr.d φDP
tgcgrcomlr.6 φA-˙B=C-˙D
tgcgrneq.1 φAB
Assertion tgcgrneq φCD

Proof

Step Hyp Ref Expression
1 tkgeom.p P=BaseG
2 tkgeom.d -˙=distG
3 tkgeom.i I=ItvG
4 tkgeom.g φG𝒢Tarski
5 tgcgrcomlr.a φAP
6 tgcgrcomlr.b φBP
7 tgcgrcomlr.c φCP
8 tgcgrcomlr.d φDP
9 tgcgrcomlr.6 φA-˙B=C-˙D
10 tgcgrneq.1 φAB
11 1 2 3 4 5 6 7 8 9 tgcgreqb φA=BC=D
12 11 necon3bid φABCD
13 10 12 mpbid φCD