Metamath Proof Explorer


Theorem tmachfullfin

Description: Folk theorem. For any algorithm deterministically processing a stream of data (essentially, an infinite tape with cell indices I and finite alphabet U ), if it terminates on every possible input, then it never looks beyond a finite portion U. ran S of the input.

Termination is expressed here with a weaker condition: that an execution may only look at a finite number of cells. Obviously, a program which finishes in a finite number of steps can only scan finite set of cells.

This theorem has many corollaries, such as: any encoding scheme able to represent all integers has at least one non-decodable tape (in other terms, encoding of the infinity).

I no longer have the source for this theorem but I believe I first read about it on LessWrong. My gratitude to Grok for suggesting that this theorem will require Axiom of Choice, and to DeepSeek for suggesting the topology-based proof route. (Contributed by Ender Ting, 28-Jul-2026)

Ref Expression
Hypotheses tmach.finalph φ U Fin
tmach.exindex φ I V
tmach.tapelist φ T = U I
tmach.scanmap φ S : T 𝒫 I Fin
tmach.agreemap φ A = z T y T | y S z = z S z
tmach.agreement φ z T y A z S y = S z
Assertion tmachfullfin φ ran S Fin

Proof

Step Hyp Ref Expression
1 tmach.finalph φ U Fin
2 tmach.exindex φ I V
3 tmach.tapelist φ T = U I
4 tmach.scanmap φ S : T 𝒫 I Fin
5 tmach.agreemap φ A = z T y T | y S z = z S z
6 tmach.agreement φ z T y A z S y = S z
7 1 2 3 4 5 6 tmachlem-franscan φ ran S Fin
8 1 2 3 4 5 6 tmachlem-fssscan φ ran S Fin
9 unifi ran S Fin ran S Fin ran S Fin
10 7 8 9 syl2anc φ ran S Fin