Metamath Proof Explorer


Theorem wl-1mintru1

Description: Using the recursion formula:

"(n+1)-mintru-(m+1)" <-> if- ( ph , "n-mintru-m" , "n-mintru-(m+1)" )

for "1-mintru-1" (meaning "at least 1 out of 1 input is true") by plugging in n = 0, m = 0, and simplifying. The expressions "0-mintru-0" and "0-mintru-1" are base cases of the recursion, meaning "in a sequence of zero inputs, at least 0 / 1 input is true", respectively equivalent to T. / F. .

Negating an "n-mintru1" operation means: All n inputs ph .. th are false. This is also conveniently expressed as -. ( ph \/ .. \/ th ) . Applying this idea here (n = 1) yields the obvious result that in an input sequence of size 1 only then all will be false, if its single input is. (Contributed by Wolf Lammen, 10-May-2024)

Ref Expression
Assertion wl-1mintru1 ⊢ if- χ ⊤ ⊥ ↔ χ

Proof

Step Hyp Ref Expression
1 tbtru ⊢ χ ↔ χ ↔ ⊤
2 1 biimpi ⊢ χ → χ ↔ ⊤
3 nbfal ⊢ ¬ χ ↔ χ ↔ ⊥
4 3 biimpi ⊢ ¬ χ → χ ↔ ⊥
5 2 4 casesifp ⊢ χ ↔ if- χ ⊤ ⊥
6 5 bicomi ⊢ if- χ ⊤ ⊥ ↔ χ