Metamath Proof Explorer


Theorem wl-1mintru1

Description: Using the recursion formula:

"(n+1)-mintru-(m+1)" <-> if- ( ph , "n-mintru-m" , "n-mintru-(m+1)" )

for "1-mintru-1" (meaning "at least 1 out of 1 input is true") by plugging in n = 0, m = 0, and simplifying. The expressions "0-mintru-0" and "0-mintru-1" are base cases of the recursion, meaning "in a sequence of zero inputs, at least 0 / 1 input is true", respectively equvalent to T. / F. .

Negating an "n-mintru1" operation means: All n inputs ph .. th are false. This is also conveniently expressed as -. ( ph \/ .. \/ th ) . Applying this idea here (n = 1) yields the obvious result that in an input sequence of size 1 only then all will be false, if its single input is. (Contributed by Wolf Lammen, 10-May-2024)

Ref Expression
Assertion wl-1mintru1 if- χ χ

Proof

Step Hyp Ref Expression
1 tbtru χ χ
2 1 biimpi χ χ
3 nbfal ¬ χ χ
4 3 biimpi ¬ χ χ
5 2 4 casesifp χ if- χ
6 5 bicomi if- χ χ