Metamath Proof Explorer


Theorem xpeq2d

Description: Equality deduction for Cartesian product. (Contributed by Jeff Madsen, 17-Jun-2010)

Ref Expression
Hypothesis xpeq1d.1 ⊢ φ → A = B
Assertion xpeq2d ⊢ φ → C × A = C × B

Proof

Step Hyp Ref Expression
1 xpeq1d.1 ⊢ φ → A = B
2 xpeq2 ⊢ A = B → C × A = C × B
3 1 2 syl ⊢ φ → C × A = C × B