Metamath Proof Explorer


Theorem xpexb

Description: A Cartesian product exists iff its converse does. Corollary 6.9(1) in TakeutiZaring p. 26. (Contributed by Andrew Salmon, 13-Nov-2011)

Ref Expression
Assertion xpexb ⊢ A × B ∈ V ↔ B × A ∈ V

Proof

Step Hyp Ref Expression
1 cnvxp ⊢ A × B -1 = B × A
2 cnvexg ⊢ A × B ∈ V → A × B -1 ∈ V
3 1 2 eqeltrrid ⊢ A × B ∈ V → B × A ∈ V
4 cnvxp ⊢ B × A -1 = A × B
5 cnvexg ⊢ B × A ∈ V → B × A -1 ∈ V
6 4 5 eqeltrrid ⊢ B × A ∈ V → A × B ∈ V
7 3 6 impbii ⊢ A × B ∈ V ↔ B × A ∈ V