Metamath Proof Explorer


Theorem 0opn

Description: The empty set is an open subset of any topology. (Contributed by Stefan Allan, 27-Feb-2006)

Ref Expression
Assertion 0opn ( 𝐽 ∈ Top → ∅ ∈ 𝐽 )

Proof

Step Hyp Ref Expression
1 uni0 ⊢ ∪ ∅ = ∅
2 0ss ⊢ ∅ ⊆ 𝐽
3 uniopn ⊢ ( ( 𝐽 ∈ Top ∧ ∅ ⊆ 𝐽 ) → ∪ ∅ ∈ 𝐽 )
4 2 3 mpan2 ⊢ ( 𝐽 ∈ Top → ∪ ∅ ∈ 𝐽 )
5 1 4 eqeltrrid ⊢ ( 𝐽 ∈ Top → ∅ ∈ 𝐽 )