Metamath Proof Explorer


Theorem 0vfval

Description: Value of the function for the zero vector on a normed complex vector space. (Contributed by NM, 24-Apr-2007) (Revised by Mario Carneiro, 21-Dec-2013) (New usage is discouraged.)

Ref Expression
Hypotheses 0vfval.2 ⊢ 𝐺 = ( +𝑣 ‘ 𝑈 )
0vfval.5 ⊢ 𝑍 = ( 0vec ‘ 𝑈 )
Assertion 0vfval ( 𝑈 ∈ 𝑉 → 𝑍 = ( GId ‘ 𝐺 ) )

Proof

Step Hyp Ref Expression
1 0vfval.2 ⊢ 𝐺 = ( +𝑣 ‘ 𝑈 )
2 0vfval.5 ⊢ 𝑍 = ( 0vec ‘ 𝑈 )
3 elex ⊢ ( 𝑈 ∈ 𝑉 → 𝑈 ∈ V )
4 fo1st ⊢ 1st : V –onto→ V
5 fofn ⊢ ( 1st : V –onto→ V → 1st Fn V )
6 4 5 ax-mp ⊢ 1st Fn V
7 ssv ⊢ ran 1st ⊆ V
8 fnco ⊢ ( ( 1st Fn V ∧ 1st Fn V ∧ ran 1st ⊆ V ) → ( 1st ∘ 1st ) Fn V )
9 6 6 7 8 mp3an ⊢ ( 1st ∘ 1st ) Fn V
10 df-va ⊢ +𝑣 = ( 1st ∘ 1st )
11 10 fneq1i ⊢ ( +𝑣 Fn V ↔ ( 1st ∘ 1st ) Fn V )
12 9 11 mpbir ⊢ +𝑣 Fn V
13 fvco2 ⊢ ( ( +𝑣 Fn V ∧ 𝑈 ∈ V ) → ( ( GId ∘ +𝑣 ) ‘ 𝑈 ) = ( GId ‘ ( +𝑣 ‘ 𝑈 ) ) )
14 12 13 mpan ⊢ ( 𝑈 ∈ V → ( ( GId ∘ +𝑣 ) ‘ 𝑈 ) = ( GId ‘ ( +𝑣 ‘ 𝑈 ) ) )
15 df-0v ⊢ 0vec = ( GId ∘ +𝑣 )
16 15 fveq1i ⊢ ( 0vec ‘ 𝑈 ) = ( ( GId ∘ +𝑣 ) ‘ 𝑈 )
17 2 16 eqtri ⊢ 𝑍 = ( ( GId ∘ +𝑣 ) ‘ 𝑈 )
18 1 fveq2i ⊢ ( GId ‘ 𝐺 ) = ( GId ‘ ( +𝑣 ‘ 𝑈 ) )
19 14 17 18 3eqtr4g ⊢ ( 𝑈 ∈ V → 𝑍 = ( GId ‘ 𝐺 ) )
20 3 19 syl ⊢ ( 𝑈 ∈ 𝑉 → 𝑍 = ( GId ‘ 𝐺 ) )