Metamath Proof Explorer


Theorem 2fveq3

Description: Equality theorem for nested function values. (Contributed by AV, 14-Aug-2022)

Ref Expression
Assertion 2fveq3 ( 𝐴 = 𝐵 → ( 𝐹 ‘ ( 𝐺 ‘ 𝐴 ) ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐺 ‘ 𝐴 ) = ( 𝐺 ‘ 𝐵 ) )
2 1 fveq2d ⊢ ( 𝐴 = 𝐵 → ( 𝐹 ‘ ( 𝐺 ‘ 𝐴 ) ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝐵 ) ) )