Metamath Proof Explorer


Theorem 2olt9o

Description: Ordinal 2 is less than ordinal 9. (Contributed by BTernaryTau, 17-Oct-2026)

Ref Expression
Assertion 2olt9o 2o ∈ 9o

Proof

Step Hyp Ref Expression
1 2on ⊢ 2o ∈ On
2 sucidg ⊢ ( 2o ∈ On → 2o ∈ suc 2o )
3 1 2 ax-mp ⊢ 2o ∈ suc 2o
4 df-3o ⊢ 3o = suc 2o
5 3 4 eleqtrri ⊢ 2o ∈ 3o
6 3olt9o ⊢ 3o ∈ 9o
7 9on ⊢ 9o ∈ On
8 ontr1 ⊢ ( 9o ∈ On → ( ( 2o ∈ 3o ∧ 3o ∈ 9o ) → 2o ∈ 9o ) )
9 7 8 ax-mp ⊢ ( ( 2o ∈ 3o ∧ 3o ∈ 9o ) → 2o ∈ 9o )
10 5 6 9 mp2an ⊢ 2o ∈ 9o