Metamath Proof Explorer


Theorem 9on

Description: Ordinal 9 is an ordinal number. (Contributed by BTernaryTau, 4-Sep-2026)

Ref Expression
Assertion 9on 9o ∈ On

Proof

Step Hyp Ref Expression
1 df-9o 9o = suc 8o
2 8on 8o ∈ On
3 2 onsuci suc 8o ∈ On
4 1 3 eqeltri 9o ∈ On