Metamath Proof Explorer


Theorem 3anasss

Description: Associative law for conjunction applied to antecedent (eliminates syllogism). Converse of 3anassrs . (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypothesis 3anasss.1 ( ( ( ( 𝜑𝜓 ) ∧ 𝜒 ) ∧ 𝜃 ) → 𝜏 )
Assertion 3anasss ( ( 𝜑 ∧ ( 𝜓𝜒𝜃 ) ) → 𝜏 )

Proof

Step Hyp Ref Expression
1 3anasss.1 ( ( ( ( 𝜑𝜓 ) ∧ 𝜒 ) ∧ 𝜃 ) → 𝜏 )
2 13an22anass ( ( 𝜑 ∧ ( 𝜓𝜒𝜃 ) ) ↔ ( ( 𝜑𝜓 ) ∧ ( 𝜒𝜃 ) ) )
3 1 anasss ( ( ( 𝜑𝜓 ) ∧ ( 𝜒𝜃 ) ) → 𝜏 )
4 2 3 sylbi ( ( 𝜑 ∧ ( 𝜓𝜒𝜃 ) ) → 𝜏 )