Metamath Proof Explorer
Description: Deduction adding conjuncts to an equivalence. (Contributed by NM, 8-Sep-2006)
|
|
Ref |
Expression |
|
Hypothesis |
3anbi1d.1 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
|
Assertion |
3anbi1d |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜃 ∧ 𝜏 ) ↔ ( 𝜒 ∧ 𝜃 ∧ 𝜏 ) ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3anbi1d.1 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
2 |
|
biidd |
⊢ ( 𝜑 → ( 𝜃 ↔ 𝜃 ) ) |
3 |
1 2
|
3anbi12d |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜃 ∧ 𝜏 ) ↔ ( 𝜒 ∧ 𝜃 ∧ 𝜏 ) ) ) |