Metamath Proof Explorer
Description: Inference adding two conjuncts to each side of a biconditional.
(Contributed by NM, 8-Sep-2006)
|
|
Ref |
Expression |
|
Hypothesis |
3anbi1i.1 |
⊢ ( 𝜑 ↔ 𝜓 ) |
|
Assertion |
3anbi1i |
⊢ ( ( 𝜑 ∧ 𝜒 ∧ 𝜃 ) ↔ ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3anbi1i.1 |
⊢ ( 𝜑 ↔ 𝜓 ) |
2 |
|
biid |
⊢ ( 𝜒 ↔ 𝜒 ) |
3 |
|
biid |
⊢ ( 𝜃 ↔ 𝜃 ) |
4 |
1 2 3
|
3anbi123i |
⊢ ( ( 𝜑 ∧ 𝜒 ∧ 𝜃 ) ↔ ( 𝜓 ∧ 𝜒 ∧ 𝜃 ) ) |