Metamath Proof Explorer


Theorem 3anbi3d

Description: Deduction adding conjuncts to an equivalence. (Contributed by NM, 8-Sep-2006)

Ref Expression
Hypothesis 3anbi1d.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
Assertion 3anbi3d ( 𝜑 → ( ( 𝜃 ∧ 𝜏 ∧ 𝜓 ) ↔ ( 𝜃 ∧ 𝜏 ∧ 𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 3anbi1d.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 biidd ⊢ ( 𝜑 → ( 𝜃 ↔ 𝜃 ) )
3 2 1 3anbi13d ⊢ ( 𝜑 → ( ( 𝜃 ∧ 𝜏 ∧ 𝜓 ) ↔ ( 𝜃 ∧ 𝜏 ∧ 𝜒 ) ) )