Metamath Proof Explorer
Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-2006)
|
|
Ref |
Expression |
|
Hypotheses |
3eqtr2d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
|
3eqtr2d.2 |
⊢ ( 𝜑 → 𝐶 = 𝐵 ) |
|
|
3eqtr2d.3 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
|
Assertion |
3eqtr2d |
⊢ ( 𝜑 → 𝐴 = 𝐷 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3eqtr2d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
2 |
|
3eqtr2d.2 |
⊢ ( 𝜑 → 𝐶 = 𝐵 ) |
3 |
|
3eqtr2d.3 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
4 |
1 2
|
eqtr4d |
⊢ ( 𝜑 → 𝐴 = 𝐶 ) |
5 |
4 3
|
eqtrd |
⊢ ( 𝜑 → 𝐴 = 𝐷 ) |