Metamath Proof Explorer


Theorem 3jaoi

Description: Disjunction of three antecedents (inference). (Contributed by NM, 12-Sep-1995) (Proof shortened by Garrett Katz, 16-Jun-2026)

Ref Expression
Hypotheses 3jaoi.1 ⊢ ( 𝜑 → 𝜓 )
3jaoi.2 ⊢ ( 𝜒 → 𝜓 )
3jaoi.3 ⊢ ( 𝜃 → 𝜓 )
Assertion 3jaoi ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 )

Proof

Step Hyp Ref Expression
1 3jaoi.1 ⊢ ( 𝜑 → 𝜓 )
2 3jaoi.2 ⊢ ( 𝜒 → 𝜓 )
3 3jaoi.3 ⊢ ( 𝜃 → 𝜓 )
4 3jaob ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) ↔ ( ( 𝜑 → 𝜓 ) ∧ ( 𝜒 → 𝜓 ) ∧ ( 𝜃 → 𝜓 ) ) )
5 1 2 3 4 mpbir3an ⊢ ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 )