Metamath Proof Explorer


Theorem 3mix2d

Description: Deduction introducing triple disjunction. (Contributed by Scott Fenton, 8-Jun-2011)

Ref Expression
Hypothesis 3mixd.1 ( 𝜑𝜓 )
Assertion 3mix2d ( 𝜑 → ( 𝜒𝜓𝜃 ) )

Proof

Step Hyp Ref Expression
1 3mixd.1 ( 𝜑𝜓 )
2 3mix2 ( 𝜓 → ( 𝜒𝜓𝜃 ) )
3 1 2 syl ( 𝜑 → ( 𝜒𝜓𝜃 ) )