Metamath Proof Explorer


Theorem 3orrabdioph

Description: Diophantine set builder for ternary disjunctions. (Contributed by Stefan O'Rear, 10-Oct-2014)

Ref Expression
Assertion 3orrabdioph ( ( { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜑 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜓 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜒 } ∈ ( Dioph ‘ 𝑁 ) ) → { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) } ∈ ( Dioph ‘ 𝑁 ) )

Proof

Step Hyp Ref Expression
1 df-3or ⊢ ( ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) ↔ ( ( 𝜑 ∨ 𝜓 ) ∨ 𝜒 ) )
2 1 rabbii ⊢ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) } = { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( ( 𝜑 ∨ 𝜓 ) ∨ 𝜒 ) }
3 orrabdioph ⊢ ( ( { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜑 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜓 } ∈ ( Dioph ‘ 𝑁 ) ) → { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( 𝜑 ∨ 𝜓 ) } ∈ ( Dioph ‘ 𝑁 ) )
4 orrabdioph ⊢ ( ( { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( 𝜑 ∨ 𝜓 ) } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜒 } ∈ ( Dioph ‘ 𝑁 ) ) → { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( ( 𝜑 ∨ 𝜓 ) ∨ 𝜒 ) } ∈ ( Dioph ‘ 𝑁 ) )
5 3 4 sylan ⊢ ( ( ( { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜑 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜓 } ∈ ( Dioph ‘ 𝑁 ) ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜒 } ∈ ( Dioph ‘ 𝑁 ) ) → { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( ( 𝜑 ∨ 𝜓 ) ∨ 𝜒 ) } ∈ ( Dioph ‘ 𝑁 ) )
6 2 5 eqeltrid ⊢ ( ( ( { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜑 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜓 } ∈ ( Dioph ‘ 𝑁 ) ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜒 } ∈ ( Dioph ‘ 𝑁 ) ) → { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) } ∈ ( Dioph ‘ 𝑁 ) )
7 6 3impa ⊢ ( ( { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜑 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜓 } ∈ ( Dioph ‘ 𝑁 ) ∧ { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ 𝜒 } ∈ ( Dioph ‘ 𝑁 ) ) → { 𝑡 ∈ ( ℕ0 ↑m ( 1 ... 𝑁 ) ) ∣ ( 𝜑 ∨ 𝜓 ∨ 𝜒 ) } ∈ ( Dioph ‘ 𝑁 ) )