Metamath Proof Explorer


Theorem 3p6e9

Description: 3 + 6 = 9. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 3p6e9 ( 3 + 6 ) = 9

Proof

Step Hyp Ref Expression
1 3cn 3 ∈ ℂ
2 1 1 1 addassi ( ( 3 + 3 ) + 3 ) = ( 3 + ( 3 + 3 ) )
3 3p3e6 ( 3 + 3 ) = 6
4 3 oveq1i ( ( 3 + 3 ) + 3 ) = ( 6 + 3 )
5 6p3e9 ( 6 + 3 ) = 9
6 4 5 eqtri ( ( 3 + 3 ) + 3 ) = 9
7 3 oveq2i ( 3 + ( 3 + 3 ) ) = ( 3 + 6 )
8 2 6 7 3eqtr3ri ( 3 + 6 ) = 9