Metamath Proof Explorer


Theorem 60lcm6e60

Description: The lcm of 60 and 6 is 60. (Contributed by metakunt, 25-Apr-2024)

Ref Expression
Assertion 60lcm6e60 ( 6 0 lcm 6 ) = 6 0

Proof

Step Hyp Ref Expression
1 6nn 6 ∈ ℕ
2 1 decnncl2 6 0 ∈ ℕ
3 60gcd6e6 ( 6 0 gcd 6 ) = 6
4 eqid ( 6 · 6 0 ) = ( 6 · 6 0 )
5 2 1 mulcomnni ( 6 0 · 6 ) = ( 6 · 6 0 )
6 2 1 1 2 3 4 5 lcmeprodgcdi ( 6 0 lcm 6 ) = 6 0