Metamath Proof Explorer


Theorem abvtrivg

Description: The trivial absolute value. This theorem is not true for rings with zero divisors, which violate the multiplication axiom; abvdom is the converse of this theorem. (Contributed by SN, 25-Jun-2025)

Ref Expression
Hypotheses abvtriv.a ⊢ 𝐴 = ( AbsVal ‘ 𝑅 )
abvtriv.b ⊢ 𝐵 = ( Base ‘ 𝑅 )
abvtriv.z ⊢ 0 = ( 0g ‘ 𝑅 )
abvtriv.f ⊢ 𝐹 = ( 𝑥 ∈ 𝐵 ↦ if ( 𝑥 = 0 , 0 , 1 ) )
Assertion abvtrivg ( 𝑅 ∈ Domn → 𝐹 ∈ 𝐴 )

Proof

Step Hyp Ref Expression
1 abvtriv.a ⊢ 𝐴 = ( AbsVal ‘ 𝑅 )
2 abvtriv.b ⊢ 𝐵 = ( Base ‘ 𝑅 )
3 abvtriv.z ⊢ 0 = ( 0g ‘ 𝑅 )
4 abvtriv.f ⊢ 𝐹 = ( 𝑥 ∈ 𝐵 ↦ if ( 𝑥 = 0 , 0 , 1 ) )
5 eqid ⊢ ( .r ‘ 𝑅 ) = ( .r ‘ 𝑅 )
6 domnring ⊢ ( 𝑅 ∈ Domn → 𝑅 ∈ Ring )
7 2 5 3 domnmuln0 ⊢ ( ( 𝑅 ∈ Domn ∧ ( 𝑦 ∈ 𝐵 ∧ 𝑦 ≠ 0 ) ∧ ( 𝑧 ∈ 𝐵 ∧ 𝑧 ≠ 0 ) ) → ( 𝑦 ( .r ‘ 𝑅 ) 𝑧 ) ≠ 0 )
8 1 2 3 4 5 6 7 abvtrivd ⊢ ( 𝑅 ∈ Domn → 𝐹 ∈ 𝐴 )