Metamath Proof Explorer


Theorem als1d

Description: Deduction rule: Given "all some" applied to a top-level inference, you can extract the "for all" part. (Contributed by David A. Wheeler, 20-Oct-2018)

Ref Expression
Hypothesis als1d.1 ⊢ ( 𝜑 → ∀∃ 𝑥 ( 𝜓 → 𝜒 ) )
Assertion als1d ( 𝜑 → ∀ 𝑥 ( 𝜓 → 𝜒 ) )

Proof

Step Hyp Ref Expression
1 als1d.1 ⊢ ( 𝜑 → ∀∃ 𝑥 ( 𝜓 → 𝜒 ) )
2 df-als ⊢ ( ∀∃ 𝑥 ( 𝜓 → 𝜒 ) ↔ ( ∀ 𝑥 ( 𝜓 → 𝜒 ) ∧ ∃ 𝑥 𝜓 ) )
3 1 2 sylib ⊢ ( 𝜑 → ( ∀ 𝑥 ( 𝜓 → 𝜒 ) ∧ ∃ 𝑥 𝜓 ) )
4 3 simpld ⊢ ( 𝜑 → ∀ 𝑥 ( 𝜓 → 𝜒 ) )