Metamath Proof Explorer


Axiom ax-bj-adj

Description: Axiom of adjunction. (Contributed by BJ, 19-Jan-2025)

Ref Expression
Assertion ax-bj-adj ∀ 𝑥 ∀ 𝑦 ∃ 𝑧 ∀ 𝑡 ( 𝑡 ∈ 𝑧 ↔ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 vx ⊢ 𝑥
1 vy ⊢ 𝑦
2 vz ⊢ 𝑧
3 vt ⊢ 𝑡
4 3 cv ⊢ 𝑡
5 2 cv ⊢ 𝑧
6 4 5 wcel ⊢ 𝑡 ∈ 𝑧
7 0 cv ⊢ 𝑥
8 4 7 wcel ⊢ 𝑡 ∈ 𝑥
9 1 cv ⊢ 𝑦
10 4 9 wceq ⊢ 𝑡 = 𝑦
11 8 10 wo ⊢ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 )
12 6 11 wb ⊢ ( 𝑡 ∈ 𝑧 ↔ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 ) )
13 12 3 wal ⊢ ∀ 𝑡 ( 𝑡 ∈ 𝑧 ↔ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 ) )
14 13 2 wex ⊢ ∃ 𝑧 ∀ 𝑡 ( 𝑡 ∈ 𝑧 ↔ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 ) )
15 14 1 wal ⊢ ∀ 𝑦 ∃ 𝑧 ∀ 𝑡 ( 𝑡 ∈ 𝑧 ↔ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 ) )
16 15 0 wal ⊢ ∀ 𝑥 ∀ 𝑦 ∃ 𝑧 ∀ 𝑡 ( 𝑡 ∈ 𝑧 ↔ ( 𝑡 ∈ 𝑥 ∨ 𝑡 = 𝑦 ) )