Metamath Proof Explorer


Theorem axc7

Description: Show that the original axiom ax-c7 can be derived from ax-10 ( hbn1 ) , sp and propositional calculus. See ax10fromc7 for the rederivation of ax-10 from ax-c7 .

Normally, axc7 should be used rather than ax-c7 , except by theorems specifically studying the latter's properties. (Contributed by NM, 21-May-2008)

Ref Expression
Assertion axc7 ( ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑𝜑 )

Proof

Step Hyp Ref Expression
1 sp ( ∀ 𝑥 𝜑𝜑 )
2 hbn1 ( ¬ ∀ 𝑥 𝜑 → ∀ 𝑥 ¬ ∀ 𝑥 𝜑 )
3 1 2 nsyl4 ( ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑𝜑 )