Metamath Proof Explorer


Theorem axc7

Description: Show that the original axiom ax-c7 can be derived from ax-10 ( hbn1 ) , sp and propositional calculus. See ax10fromc7 for the rederivation of ax-10 from ax-c7 .

Normally, axc7 should be used rather than ax-c7 , except by theorems specifically studying the latter's properties. (Contributed by NM, 21-May-2008)

Ref Expression
Assertion axc7
|- ( -. A. x -. A. x ph -> ph )

Proof

Step Hyp Ref Expression
1 sp
 |-  ( A. x ph -> ph )
2 hbn1
 |-  ( -. A. x ph -> A. x -. A. x ph )
3 1 2 nsyl4
 |-  ( -. A. x -. A. x ph -> ph )