Metamath Proof Explorer


Theorem azval

Description: An adjunction of a complex number to the ring of integers. (Contributed by AV, 30-Oct-2026)

Ref Expression
Assertion azval ( 𝑆 ∈ ℂ → ( Z[] ‘ 𝑆 ) = ( ( RingSpan ‘ ℂfld ) ‘ ( ℤ ∪ { 𝑆 } ) ) )

Proof

Step Hyp Ref Expression
1 sneq ⊢ ( 𝑠 = 𝑆 → { 𝑠 } = { 𝑆 } )
2 1 uneq2d ⊢ ( 𝑠 = 𝑆 → ( ℤ ∪ { 𝑠 } ) = ( ℤ ∪ { 𝑆 } ) )
3 2 fveq2d ⊢ ( 𝑠 = 𝑆 → ( ( RingSpan ‘ ℂfld ) ‘ ( ℤ ∪ { 𝑠 } ) ) = ( ( RingSpan ‘ ℂfld ) ‘ ( ℤ ∪ { 𝑆 } ) ) )
4 df-az ⊢ Z[] = ( 𝑠 ∈ ℂ ↦ ( ( RingSpan ‘ ℂfld ) ‘ ( ℤ ∪ { 𝑠 } ) ) )
5 fvex ⊢ ( ( RingSpan ‘ ℂfld ) ‘ ( ℤ ∪ { 𝑆 } ) ) ∈ V
6 3 4 5 fvmpt ⊢ ( 𝑆 ∈ ℂ → ( Z[] ‘ 𝑆 ) = ( ( RingSpan ‘ ℂfld ) ‘ ( ℤ ∪ { 𝑆 } ) ) )